An artist wants to make an elliptical sign out of a rectangular piece of wood. The wood piece has a length of 60 inches and a width of 40 inches. The artist wants to make the largest elliptical piece possible from the wood.

Step-by-step explanation:

The question doesn't seem complete, but the question is likely to ask for 2 things: the equation of the ellipse and it's foci. So I'll respond to that. Also, the ellipse will be at the center since the artist wants the largest.

Firstly, the equation of an ellipse at the center is given by:

(x²/a²) + (y²/b²) = 1 where a > b.

Since the artist wants to make the largest ellipse, then the length of the rectangle will be the length of the ellipse, same applies to the width.

Since the length is 60, then a = 60/2 = 30

Since the width is 40, then b = 40/2 = 20

Therefore, the equation of the ellipse is:

(x²/30²) + (y²/20²) = 1

To find the foci we need to know the center and this can be gotten by

c² = a² – b²

c² = 30² – 20² = (30 + 20)(30 – 20) = (50)(10) = 500

c = √(500) = 10√(5).

The foci, since it's at th center would be:

(–10√(5), 0) and (+10√(5), 0)