Mathematics, 12.12.2020 15:50 brookerebman15
If a projectile is launched vertically upward from 800 ft above the ground with an initial velocity of 80 ft per second, its height in feet t seconds after launch is given by s=−16t2+80t+800
.
The projectile will take seconds to return to the ground.
After seconds, the projectile will be 576 feet above the ground.
Answers: 3
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