What is the equation in point-slope form of the line passing through (-1,3) and (1, 7)? O a
y - 7 = 4(x - 1)
Ob
y-7 = 2(x - 1)
ос
y- 3 = 2(x - 1)
Od
y- 3 = 4(x + 1)

Step-by-step explanation:

The equation of the line in point slope form is expressed as;

y - y0 = m(x-x0)

m is the slope

(x0, y0) is a point on the line

Get the slope;

Given the points (-1,3) and (1, 7)

m = y2-y1/x2-x1

m = 7-3/1+1

m = 4/2

m = 2

Substitute the point m = 2 and the point (-1, 3) into the formula above as shown;

y - y0 = m(x-x0)

y - 3 = 2(x-(-1))

y - 3 = 2(x+1)

Hence the required equation is y - 3 = 2(x+1)

use formula for the circle a=3.14

step-by-step explanation:

at least two

step-by-step explanation: