1) The probability that an individual is left-handed is 12%. In a randomly selected class of 30 students, what is the probability of finding exactly 4 left-handed students? 2) Sixty-five percent of men consider themselves knowledgeable football fans. If 10 men are randomly selected, find the probability that exactly six of them will consider themselves knowledgeable fans.

0.2047

0.2377

Step-by-step explanation:

1.

What we have here is a binomial distribution

Probability p = 0.12

N = number of students in the class = 30

Probability of finding 4 left handers

P(x = 4) = 30C4 x (0.12)⁴ x (0.88)²⁶

= 27405 x 0.00020736 x 0.03602047835

= 0.2047

2.

This is also a binomial distribution

N = 10 p = 0.65

P(of 6 knowledgeable fans)

= 10C6 x (0.65)⁶ x (0.35)⁴

= 210 x 0.0754189 x 0.01500625

= 0.2377

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.