Question Find the equation of the line that is perpendicular to the given line and passes through the given point.
Enter your answer in slope-intercept form (y = mx + b ) with the values of m and b given as decimals,
rounded to the nearest hundredth if necessary.
y = 10x ; (6,-4)
The equation is y =

PLEASE ANSWER QUICKLY !!!

Step-by-step explanation:

The point-slope form of equation of a line is:

                          y - y₀ = m(x - x₀)

where (x₀, y₀) is the point which the line passes through and m is the slope of the line

The product of slopes of two perpendicular lines is  -1

so if given lines slope is 10 them:

    10·m = -1

        m = -0.1

(6, -4)     ⇒    x₀ = 6,  y₀ = -4

Therefore:

               y - (-4) = -0.1(x - 6)

               y = -0.1x + 0.6 + (-4)

                y = -0.1x - 3.4

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.