Express z 1 = 17 [ cos ⁡ ( π ) + i sin ⁡ ( π ) ] z 1 =17[cos(π)+isin(π)]z, start subscript, 1, end subscript, equals, 17, open bracket, cosine, left parenthesis, pi, right parenthesis, plus, i, sine, left parenthesis, pi, right parenthesis, close bracket in rectangular form. Express your answer in exact terms.

z1 = -17 + 0i

Step-by-step explanation:

Given the complex number z1 =17[cos(π)+isin(π)], we are to express it in rectangular form as shown;

Since cos(π) = -1 and sin(π) = 0, the equation becomes;

z1 =17[cos(π)+isin(π)]

z1 =17[(-1)+i(0)]

z1 = 17(-1 + 0i)

z1 = -17 + 0i

Hence the complex number in rectangular form is expressed as z1 = -17 + 0i

this linear equation would have just one solution.

step-by-step explanation:

the reason why this would have one solution is that it is an expression with just one variable. since that variable is not raised to a power, it will always have just one solution.