Hi guys how are you I am new to I really need help please don’t wanna fail please help Consider the equation 2(3x + 4) = ax + b
Part 1
Find one value for a and one value for b so that the equation has infinitely many solutions.

For the value of a you determined above what is the value for b so that the equation has infinitely many solutions

Support your answer. Explain your reasoning

Part 2
Find one value for a and one value for b so that the equation has no solution.

Find the value of a you determined above what is the value for b so that the equation has no solution.

Support your answer explain your reasoning.

Let's solve for a.

2(3x+4)=ax+b

Step 1: Flip the equation.

ax+b=6x+8

Step 2: Add -b to both sides.

ax+b+−b=6x+8+−b

ax=−b+6x+8

Step 3: Divide both sides by x.

ax

x

=

−b+6x+8

x

a=

−b+6x+8

x

Step-by-step explanation:

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation:

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: