let P and Q be two points of the same ordinate +2. calculate their abscissas, if P and Q belong to the circle (C).

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

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step-by-step explanation:

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