Find the equation of the circle of radius 5 units and concentric with the circles x2 + y2 - 6x + 4y + 12 = 0.

Step-by-step explanation:

x² + y² - 6x + 4y + 12 = 0

(x - 3)² + (y + 2)² = 1

Hence the equation of the concentric circle is (x - 3)² + (y + 2)² = 25.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

where are the images of the functions i can only see the question you typed.

step-by-step explanation: