Skylar owns a food truck that sells tacos and burritos. She sells each taco for $3 and each burrito for $6. Yesterday Skylar made a total of $600 in revenue from selling a total of 120 tacos and burritos. Graphically solve a system of equations in order to determine the number of tacos sold, x, x, and the number of burritos sold, yy.

She sold 40 tacos and 80 burritos.

Step-by-step explanation:

Let's define the variables:

x = number of tacos sold

y = number of burritos sold

if Skylar sold x tacos, and each taco costs $3, then the total amount she gets is:

$3*x

And if she sold y burritos, and each one costs $6, then the total amount she gets is:

$6*y

combining these two, she has:

$3*x + $6*y

We know that she made a total revenue of $600, then we have the equation:

$3*x + $6*y = $600

We also know that in total, she sold 120 tacos and burritos, then:

x + y = 120

We have the system of equations:

$3*x + $6*y = $600

x + y = 120

To solve this, we need to start by isolating one of the variables in one of the equations, i will isolate x in the second equation:

x = 120 - y

Now we can replace that in the other equation to get

$3*(120 - y) + $6*y = $600

-$3*y + $360 + $6*y = $600

($6 - $3)*y + $360 = $600

$3*y + $360 = $600

$3*y = $600 - $360 = $240

y = $240/$3 = 80

She sold 80 burritos, and we know that:

x + y = 120

x + 80 = 120

x = 120 - 80 = 40

She sold 40 tacos.

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.