This is 9thh grade math and I really need help sorry for the m

Let 'n' be the original number

Let 'a' be the digit in the ten's place of 'n'

Let 'b' be the digit in the one's place of 'n'

Then, n = 10a + b

We have,

a+b = 11 (equation 1)

Let m be the number formed when the digits of n are reversed

Then, m = 10b + a

Given that, m = n + 27

=> 10b + a = (10a + b) + 27

=> 9b - 9a = 27

=> 9(b - a) = 27

=> b - a = 3 (equation 2)

Adding equation 1 and 2, we get

2b = 14

=> b = 7

putting b = 7 in equation 1

a + 7 = 11

=> a = 4

Therefore original number is 10×4 + 7 i.e. 47

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation: