John is standing on a set of bleachers and throws a baseball into the air. the baseball lands on the field. the height of the ball, in meters, is modeled by the function shown in the graph. what's the average rate of change of the height of the ball from the point when John throws it to its maximum height?

2 m/s

Step-by-step explanation:

Given the graph of the baseball thrown into air.

John throws the baseball into the air from a given height and then the baseball reaches a maximum height and then comes back to ground.

The height of the baseball (in metres) is modeled by the function graph with respect to time.

To find:

The average rate of change of height of the ball from the point the ball is thrown to the maximum height.

Solution:

Here, the average rate of change can be found by dividing the distance between the two points with the change in time.

The starting time is 0 seconds.

The starting height is 3 metres.

The ending time is 2 seconds i.e. at which the ball reaches the maximum height.

The height is 7 metres.

Therefore, the average rate of change is:

answer: 1722

step-by-step explanation:

given: the mass of saturn=

the mass of mercury=

the number of times the mass of saturn is greater than the mass of mercury

hence, the mass of saturn is 1722 times greater than the mass of mercury.