A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the given equation. Using this equation, find out what price the widgets should be sold for, to the nearest cent, for the company to make the maximum profit. y=-15x^2+801x-5900

The widgets should be sold for $26.7 for the company to make the maximum profit.

Step-by-step explanation:

Given the quadratic equation

As the leading coefficient is (-3), so the graph would be a downward Parabola.

Thus, the maximum profit would be at the vertex.

The selling price 'x' can be determined by determining the x-coordinate of the vertex.

In order to calculate the x-coordinate of the vertex, we can find this by

x = -b/2a

where a = -15 and b = 801

x = -801 / 2(-15)

x = -801/-30

x = 801/30

x = 267/10

x = 26.7

Therefore, the widgets should be sold for $26.7 for the company to make the maximum profit.

70.30

step-by-step explanation:

(a) {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …}

(b) $59 398

step-by-step explanation:

(a) the annual sequence of profits

aₙ = a₁rⁿ⁻¹

the model for the sequence of profits is {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …} .

(b) profit after 15 yr

  a₁ = $ 30 000

  r = 1.05

a₁₅ = 30 000 × 1.05¹⁴

a₁₅ = 30 000 × 1.979 93

a₁₅ = $59 398

the profit in year 15 will be $59 398.