Mathematics, 31.01.2020 04:05 20cschultz

Solve this problem on paper using all four steps.

a girl scout troop sold cookies. if the girls sold 5 more boxes the second week than they did the first, and if they doubled the sales of the second week for the third week to sell a total of 431 boxes of cookies, how many did they sell each week?

so i'm supposed to figure this out using a single variable. since the only week that isn't based on another week number is week one. i'm using it as x (variable). so week 1 is x, week 2 is x + 5, and week three is 2x + 5. so if i'm correct the equation to solve it should be x + x + 5 + 2x + 5 = 431. after simplifying it comes to 4x + 10 + 431. then you subtract 10 from both sides and multiply both sides by the reciprocal of 4 to get the let side to only have x. which i subtract the 10 and get 4x = 421. after multiplying by the reciprocal of 4 (1/4? ) however. i get a decimal. and i'm pretty sure you can't sell a quarter of a box of cookies.

tell me what i'm doing wrong?

Answers: 2

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Answers

Your mistake is that week 3 is twice of week 2
week2=x+5, twice of that is 2(x+5)=2x+10, you did not distribute the 2 to the 5 and you got 2x+5, that is your mistake

x is first week
2nd week is y
3rd is z

5 more the 2nd week than 1st week
x+5=y

3rd week is double 2nd wee
z=2y

total is 431

x+y+z=431
sub
y=5+x and z=2y
x+5+x+2y=431
sub 5+x for y
x+5+x+2(5+x)=431
x+5+x+10+2x=431
4x+15=431
minus 15
4x=416
divide by 4
x=104
add 4
x+5=109
double
2*109=218

they sold
1st week: 104
2nd week: 109
3rd week: 218

Answer from: Quest

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

Answer from: Quest

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring). so find the distance between (1,2) and (4,2). that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3. it is a regular polygon which means all sides are congruent. you have 6 sides (hexa) so multiply 6 by 3 to receive 18.

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