A student draws a card at random from the cards shown. Without replacing the card,
1
he draws a second card.
E
P
E
N
D
E
N
T
E
V
E
N
T
S
What is the probability that the student will
draw two consonants?
A
3
7
с
2
91
N
WN ON
B
1
35

Explanation:

We have a 5 by 3 grid of letters. There are 5*3 = 15 letters total.

Of that total, there are 5 vowels (2 'e's in row 1, 2 'e's in row 2, and 1 'e' in row 3)

So there are 15-5 = 10 consonants.

The probability of pulling out a consonant is 10/15 = 2/3

After selecting that consonant, we have 10-1 = 9 consonants left out of 15-1 = 14 letters total.

The probability of selecting a second consonant, after not replacing the first selection, is 9/14.

Multiply the two fractions found:

(2/3)*(9/14) = (2*9)/(3*14) = 18/42 = 3/7

To reduce 18/42, we divide both parts by the GCF 6, which is how we end up with 3/7.

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°