The area of a rectangle is 28x6y9 square feet. If the length of the rectangle is 14x3y3 feet, which expression represents the width of the rectangle?

W = 2*x^3*y^6

Step-by-step explanation:

For this problem, we need to use the relationship:

a^x/a^y = a^(x - y)

For a rectangle with length L and width W, the area is:

A = L*W

We know that in this case we have:

A = 28*x^6*y^9

and:

L = 14*x^3*y^3

We want to find the value of W.

Using the above equation, we have that:

A = 28*x^6*y^9 = L*W = (14*x^3*y^3)*W

28*x^6*y^9 = (14*x^3*y^3)*W

We can solve this for W by isolating it in the right side.

First, let's divide by 14 in both sides to get:

(28*x^6*y^9)/14 = (14*x^3*y^3)*W/14

(28/14)*x^6*y^9 = (14/14)*x^3*y^3*W

2*x^6*y^9 = x^3*y^3*W

Now let's divide by x^3 in both sides to get:

(2*x^6*y^9)/x^3 = (x^3*y^3*W)/x^3

2*(x^6/x^3)*y^9 = (x^3/x^3)*y^3*W

Now we use the relationship that is in the beginning:

2*x^(6 - 3)*y^9 = y^3*W

2*x^3*y^9 = y^3*W

Now let's divide by y^3 in both sides:

(2*x^3*y^9)/y^3 = (y^3*W)/y^3

2*x^3(y^9/y^3) = (y^3/y^3)*W

2*x^3*y^(9 - 3) = W

2*x^3*y^6 = W

The width of the rectangle is given by the equation:

W = 2*x^3*y^6

step-by-step explanation:

is their an equation anywhere i can take a   look at it and see if i am right.

3,6 and 7.

step-by-step explanation:

a) unit place of 37 is 7

so the unit place of cube of 37 will be

7³= 343=3

the answer is 3.

b) unit place of 56 is 6, so the unit place of cube of 56 will be

6³= 216=6

the answer is 6.

c) unit place of 133 is 3, so the unit place of cube of 133 will be

3³= 27= 7.

the answer is 7.