[tex]40-23\frac{6}{7} A \\17\frac{1}{7} B \17\frac{6}{7} C \16\frac{1}{7} D \16\frac{6}{7}[/tex]

Step-by-step explanation:

40 minus 23 and six-sevenths

A. 17 and one-seventh

B. 17 and six-sevenths

C. 16 and one-seventh

D. 16 and six-sevenths

30

step-by-step explanation:

idk

i hope i

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.