HELLLPP PLSSS Given point (-6, -3) and a slope of 4, write an equation in point-slope form.
a. y - 3 = 4(x - 6)
b. y + 3 = 4(x - 6)
c. y + 3 = 4(x + 6)
d. y - 3 = 4(x + 6)

Given point (-6, -2) and a slope of 5, write an equation in slope-intercept form.

a. y = 5x + 28
b. y = -5x + 28
c. y + 2 = 5(x + 6)
d. y - 2 = 5(x - 6)

Given point (-3, -5) and a slope of 2, write an equation in point-slope form.
a. y + 5 = 2(x - 3)
b. y - 5 = 2(x - 3)
c. y + 5 = 2(x + 3)
d. y - 5 = 2(x + 3)

Given point (7, -2) and a slope of 1, write an equation in slope-intercept form.
a. y = x + 9
b. y = x - 9
c. y + 2 = 1(x + 7)
d. y + 2 = 1(x - 7)

angle q= 92 degree

step-by-step explanation:

the solution is in the picture

when a quadrilateral is inscribed in a circle, the opposite angles are supplement to each other. in other words, the sum of the 2 angle is 180 degree

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180