What is the equation of the line that passes through the points 1/2/3 and (-1,-1 a. y=-6x+5

b. Y=5/6X-1/6

C. Y=2/3X+1/5

D. y=6/5x+1/5

(1, 2/3) (-1, -1) are the points. use the slope formula to find the slope y2-y1/x2-x1

(-1 - 2/3) / (-1 -1) (answer both sides of the division side)

-5/3 / -2  (divide)

slope = 5/6  (the slope)

plug in values you know into point-slope form (y -y1) = m(x-x1)

y - (-1) = 5/6 (x - (-1) (i chose the easier point to plug in. two neg. make a pos. )

y +1 = 5/6 (x +1)  (use the distributive property)

y +1 = 5/6x+5/6  (subtract 1 from both sides)

y = 5/6x - 1/6  or B (this is the equation)

Step-by-step explanation:

I hope this helped :))

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step-by-step explanation:

i think the answer is b