On a certain hot summer's day, 291 people used the public swimming pool. The daily prices are $1.50 for children and $2.00 for adults. The receipts for admission totaled $472.50 How many children and how many adults swam at the public pool that day?

219 children and 72 adults swam at the public pool that day.

Step-by-step explanation:

Let x = Number of children , y= Number of adults.

As per given,  x+y = 291      (i)

1.5x+2y = 472.50         (ii)

Multiply 2 on both sides of (i) , we get

2x+2y = 582  (iii)

Eliminate (ii) from (iii), we get

0.5x = 109.5

Put value of x= 219 in (i)

219+y= 291

⇒ y = 291-219 = 72

Hence, 219 children and 72 adults swam at the public pool that day.

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

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