Astorage area measures 12 feet 6 inches in width by 16 feet in length by 8 feet 3 inches in height. if it is 4/5 full, how many cubic feet of storage space remains (rounded to the nearest cubic foot)?

1 ft = 12 in
1 ft e 6 in = 18 in
largura = 18 in
comprimento = 16 in
altura = 8 ft + 3 in = 96 in + 3 in = 99 in
volume = 18*16*99
volume = 28512 in³

4/5 * 28512 = (4*28512)/5 = 22809,5 in³ (cheio)
1/5 * 28512 = 28512/5 = 5702,4 (vazios)

6/9 i need more characters in my answer