Which is the equation in the slope-intercept form of the line that contains points E & F ? •4x-y=12
•y-4=4(x-4)
•x-4=4(y-4)
•y=4x-12

y = 4x - 12

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m =

with (x₁, y₁ ) = E(4, 4) and (x₂, y₂ ) = F(2, - 4)

m = = = 4 , then

y = 4x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (4, 4), then

4 = 16 + c ⇒ c = 4 - 16 = - 12

y = 4x - 12 ← equation of line

360 different combinations

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.