Answer fast...Show work on both

A) 14.3606 ft

B) 2.8112 seconds

Step-by-step explanation:

A) At maximum height which is its peak, the velocity will be zero.

Now, we are given height modeled by;

h(t) = 4.98t² - 14t + 20

v(t) = dh/dt = 9.96t - 14.

At max height which is v(t) = 0, we have;

9.96t - 14 = 0

9.96t = 14

t = 14/9.96

t = 1.4056 s

Thus, height at this time is;

h(1.4056) = 4.98(1.4056)² - 14(1.4056) + 20

h(1.4056) = 14.3606 ft

B) time of flight = 2 × time to get to peak = 2 × 1.4056 = 2.8112 seconds.