15 What is the equation, in point-slope form, of the line that
is parallel to the given line and passes through the point
(-3, 1)?
-4
3
2
(2, 2)
(-3, 1)
1.
5 -4 -3 -2 -14
2
3
4
5
X
2.-
O y-1=-} (x+3)
O y-1=- (x + 3)
O y-1= }(+3)
O y-1= {x+3)
3
-2,-4)

yes

Step-by-step explanation:

sorry i need points

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.