Subject A is traveling at a constant speed ahead of subject B. If B raises its speed by 4 times, it will catch up with A in 30 minutes. If B raises its speed by 5 times, it will catch up with A in 20 minutes. How many minutes it will take for B to catch up with A if B raises its speed 6 times?

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

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two? xd

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you could deduce the conclusion directly using the facts pertaining to the specific situation.

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step-by-step explanation: could you give me 5 stars