Using either substitution or elimination method, solve the system of equations that consists of 8x+y= -16 and -3x+y=-5 Your solution will be a coordinate of integers. ​

x= -1

y= -8

Step-by-step explanation:

Solve for y in 8x + y = -16

y = -16 - 8x

Substitute y = -16 - 8x into -3x + y = -5

-11x - 16 = -5

Solve for x in -11x - 16 = -5

x = -1

Substitute x = -1 into y = -16 - 8x

y = -8

Therefore,

x= -1

y= -8

(-1, -8)

Step-by-step explanation:

SUBSTITUTION METHOD:

Solve for y in the first equation by subtracting 8x from both sides.

Substitute this value for y into the second equation.

Remove the parentheses and simplify.

Combine like terms.

Add 16 both sides of the equation.

Divide both sides of the equation by -11.

Substitute this value for x into either equation (I'm using the first equation).

Multiply and simplify.

Add 8 to both sides of the equation.

ELIMINATION METHOD:

Subtract the second equation from the first equation to "cancel" the y-variable.

Divide both sides of the equation by 11.

Substitute this value for x into either equation (I'm using the second equation).

Multiply and simplify.

Subtract 3 from both sides of the equation.

The solution to this system of equations is (-1, -8).

step-by-step explanation:

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