The lcm of 120 and n is 2520. Find the smallest value of n. Please explain the answer. Thank you.

The smallest value of n is:

n = 21

Step-by-step explanation:

We know that the LCM (least common multiple) between 120 and n is 2520.

We want to find the smallest value of n.

The smallest value of n will be such that n does not share any prime number with 120, then the greatest common factor between 120 and n is 1.

Remember that the LCM between A and B is:

LCM(A, B) = A*B/(GCM(A, B))

Then if the greatest common factor between A and B is 1, we will have:

LCM(A, B) = A*B

Then if the greatest common factor between 120 and n is 1, we have that:

LCM(120, n) = 120*n = 2520

then:

n = 2520/120 = 21

The smallest value of n is n = 21.

15%

step-by-step explanation:

use the table and count the number of guesses that has two correct answers.

the following are two correct answers

10010, 01100, 11000

a total of 3 numbers having 2 correct guesses out of 20 questions.

probability of getting 2 correct guesses = the number of questions getting 2 correct answers / total number of questions.

= 3/20

to convert it into percent multiply by 100, we get

= 3/20 * 100

= 15%

the answer is 15%

you.

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.