In ΔQRS, the measure of ∠S=90°, QS = 11, SR = 60, and RQ = 61. What is the value of the sine of ∠Q to the nearest hundredth?

0.98

Step-by-step explanation:

Below is a drawing of the triangle (drawing it out is an important step if you have trouble visualizing it).

Sine = opposite/hypotenuse, in this case, SR (60) is the opposite of angle Q and RQ (61) is the hypotenuse.

Sin(angle Q) = 60/61 = 0.98

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

the answer is z7+8/5