Prompt: Sasha wants to go to the department store this Saturday for the big sale. She has saved $45, received $75 from birthday gift cards, and will receive $125 on Friday from work. Her mother reminds Sasha of the $39 she owes her for the last pair of jeans. Sasha also needs to put $50 in her savings. The sale has $40 jeans at 20 percent off and T-shirts on sale for 3 for $15.99. How many pairs of jeans and T-shirts can Sasha purchase? Show or explain how you got your answer.

Step-by-step explanation:

Given that :

Inflow for Sasha = $(45 + 75 + 125) = $245

Outflow = $(39 + 50) = $89

Amount shasha can spend on sale :

$(245 - 89) =$156

T- shirt sales = 3 for $15.99

Pair of Jeans = (1 - 0.2) = 0.8 * $40 = $32

3 pairs of jeans

12 T-shirts at 3 for $15.99

3 jeans = 3 * $32

T - si

answer: sorry

step-by-step explanation: can you tell me pls how to find the rational of two integers

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2