Last month you swam the 50 meter freestyle in 28.38 seconds. Today you swam it in 27.33 seconds. What is your percent of change? Round to the nearest tenth of a percent if necessary.

The distance is the same(50 meters). So we will operate only with numbers 28.38 and 27.33.

The difference is 28.38-27.33=1.05

So the percent of change is (1.05/28.38)*100%≈3.7%

The answer is 3.7%

Step-by-step explanation:

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b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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step-by-step explanation: