The length of the hypotenuse in a 45° - 45° - 90' triangle is 7/10 units. One of the legs is 7V5 units. What is the length of the other leg? 7V5units
O 145units
035 units
070 units

step-by-step explanation:

i hate black

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation:

inverse property is the answer

step-by-step explanation:

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west