01-Duas cargas pontuais positivas, Q1 = 23C, é colocada a uma distância r = 3,0 cm de outra carga também pontual, negativa, Q2 = -0,60_C.
Suponha que as cargas Qie Q2 estejam no ar, calcule o valor da
força F1 que Q2 exerce sobre Q1​

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

what is the approximate angle of acb if abc is 25cm and the length of segment bc is 15

step-by-step explanation:

answer: the answer is 30 miles per hour.

ft/s -> mphmph = ft/s 1.466667mph = 44 divided by 1.466667mph = 30.00000

- r3ktforgood ☕

the answer is c.

step-by-step explanation: