Help! Use the identity of i^2=-1 to compute the powers of i and complete the table

Step-by-step explanation:

i^3= -i

i^4= 1

i^5= i

i^6= -1

i^7=  -i

For the other questions, can you give me the value of N. If that is not possible, then sorry I can not help you. And feel free to report this if this is not useful :(

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

what is the answer?