Prove that if n is an even integer, then n + 1 is odd. Give a proof by contraposition of this theorem.

Proved below

Step-by-step explanation:

If we assume that n + 1 even when n is even, it means that;

n + 1 = 2x

Where x is an integer

Then;

n = 2x - 1

This means that n is odd because 2x - 1 is odd.

But we know that n is even, thus, our assumption is wrong.

Therefore, n + 1 is odd when n is even.

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

idk

step-by-step explanation:

use that smart brain