Write the first four terms of the sequence.

f(n) = (n-1) (n-2)

the first four terms are 0,0,2,6

Step-by-step explanation:

The computation of the first four terms of the sequence is shown below:

Given that

f(n) = (n - 1) (n -2)

= n^2 - 2n - n + 2

= n^2 - 3n + 2

Now the first four terms are

f(1) = 1^2 - 3(1) + 2

= 1 - 3 + 2

= 0

f(2) = 2^2 - 3(2) + 2

= 4 -6 + 2

= 0

f(3) = 3^2 - 3(3) + 2

= 9 - 9 + 2

= 2

f(4) = 4^2 - 3(4) + 2

= 16 - 12 + 2

= 18 - 12

= 6

So, the first four terms are 0,0,2,6

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3

option 1

data plot with   3 dots over 33, 1 dot over 34, 2 dots over 35, no dot over 36, 1 dot over 37, 2 dots over 38, 4 dots over 39, and 2 dot over 40.