Wire mesh enclosures for two batting cages are to be built side by side at a school. If each cage needs 240 m3 of space, what is the minimum amount of wire mesh needed, where ? (Wire mesh is not needed on the bottom of the cage.)

answer: finding the extract measurements and knowing the points

step-by-step explanation:

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x

4

step-by-step explanation:

im pretty sure it's 4 beacsue 8/2 equals 4