What is the distance between (0.-3) and (9.6)

d = 12.7  when rounded to the nearest tenths

Step-by-step explanation:

Distance formula:

d=√((x_2-x_1)²+(y_2-y_1)²)

Your ordered pairs (0, -3) and (9, 6)

d=√((9-0)²+(6-(-3))²)

d=√((9))²+(6+3))²)

d=√(81 + (9)²)

d = √162

d = 12.727...

d = 12.7  when rounded to the nearest tenths

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~