A dragonfish is swimming at -900 m relative to sea level. It rises 250 m. What is the dragonfish´s new depth relative to sea level? Show your work.

1150 m

Step-by-step explanation:

Given that,

A dragonfish is swimming at -900 m relative to sea level.

It rises 250 m.

We need to find the dragonfish´s new depth relative to sea level. Let the new position is x. So,

x = 250-(-900)

= 250+900

= 1150 m

Hence, the new position is 1150 m.

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

happy to

pls mark as brainliest

true

step-by-step explanation: