Mathematics, 18.03.2021 01:20 ptrlvn01
Dogs vary in size a great deal more than cats do. Suppose the mean weight of dogs in a certain city is 28 pounds with a standard deviation of 14 pounds, and the mean weights of cats is 9.5 pounds with a standard deviation of 2 pounds. Cat weights are roughly Normally distributed, but dog weights are skewed right. Suppose you take a random sample of 10 dogs and 8 cats. Which of the following is an accurate description of the center, spread, and shape of the sampling distribution of the difference in the mean weight dogs and the mean weight of cats?
(a) Mean = 18.5 pounds, standard deviation = 4.48 pounds, shape approximately Normal
(b) Mean = 18.5 pounds, standard deviation = 4.48 pounds, shape non-Normal
(c) Mean = 18.5 pounds, standard deviation - 14.1 pounds, shape approximately Normal
(d) Mean = 18.5 pounds, standard deviation = 14.1 pounds, shape non-Normal
(e) The difference of means is 18.5 pounds and the shape is non-Normal, but the standard deviation cannot be determined since the sample size is small and the distribution of dog weights is non-Normal.
Answers: 3
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Dogs vary in size a great deal more than cats do. Suppose the mean weight of dogs in a certain city...
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