What is the standard form of the following equation? y= 2(x - 1)^2 + 4

A) y = 2x2 + 4
B) y = 2x² - 4x + 8
C) y = 2x2 – 2x + 4
D) y= 2x2 - 4x + 6​

y = 2(x - 1)² + 4

y = 2(x² - 2x + 1) + 4

y = 2x² - 4x + 2 + 4

y = 2x² - 4x + 6

b

step-by-step explanation:

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3