For positive acute angles A and B it is known that sinA= 35/37 and tanB= 7/24. find the value of (A-B)

54.8° to the nearest tenth of a degree

Step-by-step explanation:

m∠A = arcsin 35/37 = 71.075...

m∠B = arctan 7/24 = 16.2602...

m∠A - m∠B = 71.075 - 16.260 = 54.8° to the nearest tenth of a degree

eve and marks ratios are equivalent

step-by-step explanation:

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°