Which of the f-values satisfy the following inequality? f+8< 12
Choose all answers that apply:
A f= 4
B f = 5
C f=6

F<12-8

F<4 thefore the answer is F<4

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐