An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 140 lb and 191 lb. The new population of pilots has normally distributed weights with a mean of 148 lb and a standard deviation of 30.3 lb. a. If a pilot is randomly​ selected, find the probability that his weight is between 140 lb and 191 lb.

The probability is approximately . ​(Round to four decimal places as​ needed.)

The probability is approximately 0.3193

Step-by-step explanation:

The question parameters;

The mass between of the pilot for which the seat was designed, = 140 lb and 191 lb

The mean weight of the new pilots, μ = 148 lb

The standard deviation of the weights new pilots, s = 30.3 lb

a. The z-score is given as follows;

Therefore, we have;

The p-value = 0.60257

The p-value = 0.9222

The probability that the mean lie between the two values = 0.9222 - 0.60257 = 0.31963

Therefore, the probability that the weight is between the 140 lb and 191 lb ≈ 0.3196

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!