Which set of integers is ordered from least to greatest -13 , 4, 0, -8 -5 , -2, 3, 1 -12 , -18 , -4 , 7 -15, 6 , -9 , -21

Given:

The set of integers in the options.

-13 , 4, 0, -8

-5 , -2, 3, 1

-12 -18 , -4 , 7

-15, 6 , -9 , -21

To find:

The set of integers that is ordered from least to greatest.

Solution:

We know that the larger negative value is the smaller value and the larger positive value is the greater value.

Ordered from least to greatest means first we need to write the smallest value, write the value larger than and the greatest value occurs at the end.

In option A, we have -13 , 4, 0, -8. Here, 4>0. So, the option A is incorrect.

In option B, we have -5 , -2, 3, 1. Here, 3>1. So, the option B is incorrect.

In option C, we have -12 -18 , -4 , 7 Here, -12>-18. So, the option C is incorrect.

In option D, we have -15, 6 , -9 , -21. Here, 6>-9. So, the option D is incorrect.

Therefore, all the options are incorrect.

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)