1.there are 10 kids running a race. how many ways are there for them to come in first, second, and third place?

2.in a drawing, a jar holds the numbers 1 to 8. if you draw three numbers to form a three-digit number (without replacement), what is the probability you will draw 135?

1: 720

2:

Step-by-step explanation:

1: There are 10 kids in a race so the number of ways such that they come first , second and third=10×9×8

                           =720

(since the first place is occupied by any one of the ten students i.e. we have ten choices after occupying first position there are only 9 students left for second position and after occupying second for the third position only 8 choices are left)

2: We have to find the probability such that there is no replacement  such that we draw 135.

for the first position we have to find the probability() that '1' comes out of 8 numbers=

similarly for second choice we could not take 1 as there is no replacement

so probability that 3 comes() =

similarly probability that 5 comes at third position() =

hence, probability that 135 is drawn=

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )