The sample mean tip amount for the 20 parties to which the waitress gave her name was $5.44, with a standard deviation of $1.75. These statistics were $3.49 and $1.13, respectively, for the 20 parties to which the waitress did not give her name. The data were not strongly skewed in either group. Required:
Use appropriate symbols for the six numbers reported in this paragraph.

First sample size, = 20

Second sample size, = 20

Sample mean of first sample, = 5.44

Sample mean of second sample, = 3.49

Sample Standard deviation of first sample, = 1.75

Sample Standard deviation of second sample, = 1.13

Step-by-step explanation:

Given - The sample mean tip amount for the 20 parties to which the waitress gave her name was $5.44, with a standard deviation of $1.75. These statistics were $3.49 and $1.13, respectively, for the 20 parties to which the waitress did not give her name. The data were not strongly skewed in either group.

To find - Use appropriate symbols for the six numbers reported in this paragraph.

Proof -

First sample size, = 20

Second sample size, = 20

Sample mean of first sample, = 5.44

Sample mean of second sample, = 3.49

Sample Standard deviation of first sample, = 1.75

Sample Standard deviation of second sample, = 1.13

answer: what

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.