1,find the equation of the line with y-intercept (0,8) and slope ⅗. 2,Find the slope and y-intercept of y=10x-⅓. 3,Find the slopes of the lines containing these points. a) (4,-3) and (6,-4) b)

1) y = 3/5x + 8

2) Slope: 10

   y-intercept: -1/3

3) y = -1/2x - 1

Step-by-step explanation:

1) The equation you need to refer to for this problem is y = mx+b

m = slope (3/5 for this problem)

b = y-intercept(which is 8)

plug those numbers in and you get y = 3/5x + 8

2) look back at this equation: y = mx+b

10 is the slope and -1/3 is the y-intercept

3) This one is a bit more difficult as you need two other formulas to solve:

the slope formula, y1 - y2/x1 - x2, and the point-slope formula,

y - y1 = m(x - x1)

For this problem, you have the coordinates (4, -3) and (6, -4) which you would plug into the slope formula, like this:

-3 -(-4)/4 - 6 = -1/2

the numbers 1 and 2 in this formula refer to the first (x,y) value and the second. You subtract the two y values and the two x values, simplify, and you get your answer.

-1/2 is going to be the m, or slope, that you will use in the second formula, the point slope formula, y - y1 = m(x - x1)

To solve this you choose one of the original coordinates that you were given to plug into the y1 and x1, and plug -1/2, your slope, in for m:

(keep in mind, for this, I used (4,-3) but you can use either one)

y -(-3) = -1/2(x - 4)

To solve this you, first, distribute -1/2 to x and -4 inside the parentheses:

y -(-3) = -1/2x + 2

Then, on the other side, add the to negatives to get a positive 3:

y + 3 = -1/2x + 2

and subtract 3 from both sides:

y = -1/2x - 1

I hope this isn't too confusing

good luck!

yep

step-by-step explanation: