If two numbers are in the ratio 6:13 and their LCM is 312, then find the numbers.​

The two numbers are 12 and 26

Step-by-step explanation:

let the first number = a

let the second number = b

The ratio of the numbers is given as;

-------- (1)

The lcm of the two numbers is given as;

a x b = 312

ab = 312 --------- (2)

From equation (1),

Therefore, the two numbers are 12 and 26

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x

current in the circuit at time t is /, then the power delivered to the resistor is

step-by-step explanation: