Mathematics, 28.11.2019 01:31 Braxton12
Find the area of the surface of revolution generated by revolving the curve y = 3 sqrt (x), 0 < = x < = 4, about the x-axis.
okay, so i've set up the integral like this: 2pi ∫[0,4] (3 sqrt ((1+(1/ which is coming out to 108.5, but that's not giving me the right answer. can you me set up the integral correctly or tell me what i'm doing wrong?
Answers: 2
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Find the area of the surface of revolution generated by revolving the curve y = 3 sqrt (x), 0 < =...
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