Find the surface area of the regular hexagonal pyramid. round your answer to the nearest hundredth.

113.56sq.ft.

Step-by-step explanation:

The side of the hexagon is represented by "s" = 4 ft

Apothem (perpendicular drawn from the center to any of side) represented  "a"= 2√3

"l" be the slant height (height of the triangle) of the pyramid= 6 ft.

Formula of total surface area = 3s (l + a)

                                                =3*4(6+2√3)

                                                =12(6+2*1.73205080757)

                                                 =12(6+3.46410161514)

                                                 = 12(9.46410161514)

                                                  = 113.569219382

Thus the surface area of the regular hexagonal pyramid = 113.569219382sq.ft.

the diagram shows you   triangle def with de=4, df=9 and de≠df≠ef.

the sum of the lengths of two triangles' sides are always greater than the length of the third side:

substitute sides lengths:

then 5< ef< 13 (option 3 is true).

def is a scalene triangle with all sides of different lengths (option 5 is true, option 2 is false).

answer: correct choices are 1, 3 and 5